NC assignment 2:

 NC assignment 2:

answer of question 2 = 122.2425 above answer is wrong correct it

answer of question 3 = 0.82383

code:

# Given data

h = 50  # Step size

p = 0   # p = (x - x0)/h = 0 at x = 200

# Use correct backward difference values

nabla2_f0 = 25  # Second backward difference at x = 200

nabla3_f0 = 5   # Third backward difference at x = 200

# Applying backward second derivative formula:

# f''(x0) = (1/h^2) * [∇²f0 + ((6p + 6)/3!) * ∇³f0]

second_derivative = (1 / h**2) * (nabla2_f0 + ((6 * p + 6) / 6) * nabla3_f0)

# Output the result

print(f"Approximate second derivative at x = 200 is: {second_derivative:.3f} ms/user²")